Toy compiler

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Information about Toy compiler

Published on October 6, 2015

Author: NarendranIlango


1. Toy Compiler

2. Toy compiler Front end : It performs lexical , syntax and semantic Involved functions… 1.Determining validity of a source statement from the view point of analysis. 2.Determine the “content” of source statement. 3.Construct a suitable representation of the source statement for being used by subsequent analysis function (or)the synthesis phase of the language processor.

3. FrontEnd… •Lexical analysis=Content in lexical class. •Syntax analysis=syntactic structure of source statement. •Semantic analysis=In meaning of statement _ For a declaration statement _ It is set of attributes of a declared variable Example: Type, length and dimensionality

4. FrontEnd… Output of Front end: 1.Tables of information. 2.An intermediate code which is the description of the source program.

5. Analysis phase for the program.. I : integer; a ,b :=real; a :=b+I; Symbol table: Intermediate code: 1.Convert(Id,#1)to real , giving(Id,#4) 2.Add(Id,#4)to(Id,#3),giving(Id,#5) 3.Store(Id,#5)in(Id,#2) Symbol type length address i int a real b real i* real Temp real

6. Lexical analysis(scanning): Identifies lexical units in source statement.Its Classifies units into different lexical classes. Eg: id’s,constants,reserved id’s etc. Eg:the statement a := b+i represented as string of tokens. Id#2 Op#5 Id#3 OP#3 Id#1 Op#10

7. Syntax Analysis: Syntax analysis processes the string of tokens built by lexical analysis to determine the statement classes. Eg: assignment statement,if statement ,etc.. real := a b a + b i

8. •Semantic Analysis: := := := a,real + a,real + a,real temp,real b,real i,int b,real i*,real

9. Back End: • Involves Two phases • Memory Allocation • Code Generation

10. Memory Allocation • It is a simple task given the presence of the symbol table. • The memory requirement of an identifier is computed from its type,length,dimensionality and memory is allocated • For example Symbol Type Length Address 1 i int 2000 2 a real 2001 3 a real 2002

11. Code Generation • It uses knowledge of the target architectue i.e.. Knowledge of instructions and addressing modes • Issues • 1.Detremine the places where the intermediate results to be kept (either on memory locations or in machine registers) • 2.Determine which instruction should be used for type conversion • 3.determine which addressing mode to be used while accessing variables.

12. Code Generation • a:=b+i • 1.convert I to real, giving i* • 2.add i* to b giving temp • temp in a • Synthesis phase may decide to hold values of i* and temp in machine register and may generate assembly code • CONV_R AREG,I • ADD_R AREG,B • MOVEM AREG,A

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