# Ssc cgl-numerical-aptitude-basic-algebra

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Published on March 4, 2014

Author: upscportal

Source: slideshare.net

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SSC-CGL-Numerical-Aptitude-Basic-Algebra.pdf

http://sscportal.in Online Coaching by SSCPORTAL Staff Selection Commission Combined Graduate Level [Tier-1] Subject : Numerical Aptitude Chapter : Basic Algebra © SSCPORTAL.IN SSC EXAM Online Coaching

Numerical Aptitude http://sscportal.in Basic Algebra A Civil Servant should be well-versed in basics of Algebra. In the Civil Services Aptitude Test Paper 2, in Basic Numeracy, certainly there will be asked some questions based on equations and their roots. © 2014 SSCPORTAL .IN Join Online Coaching Click Here

Numerical Aptitude http://sscportal.in Basic Algebra Polynomials An expression in term of some variable(s) is called a polynomial. For example f(x) = 2x – 5 is a polynomial in variable x g(y) = 5y2 – 3y + 4 is a polynomial in variable y © 2014 SSCPORTAL .IN Join Online Coaching Click Here

Numerical Aptitude http://sscportal.in Basic Algebra Degree of a Polynomial The exponent of the highest degree term in a polynomial is known as its degree. Linear Polynomial A polynomial of degree one is called a linear polynomials. In general f(x) = ax + b, where a ¹ 0 is a linear polynomial. © 2014 SSCPORTAL .IN Join Online Coaching Click Here

Numerical Aptitude http://sscportal.in Basic Algebra Quadratic Polynomials Cubic Polynomial Bi-quadratic Polynomial Zero of a Polynomial Remainder Theorem Factor Theorem © 2014 SSCPORTAL .IN Join Online Coaching Click Here

Numerical Aptitude http://sscportal.in Basic Algebra Useful Formulae (i) (x + y)2 = x2 + y2 + 2xy (ii) (x – y)2 = x2 + y2 – 2xy (iii) (x2 – y2) = (x + y) (x – y) (iv) (x + y)3 = x3 + y3 + 3xy(x + y) (v) (x – y)3 = x3 – y3 – 3xy(x – y) (vi) (x3 + y3) = (x + y) (x2 + y2 – xy) (vii) (x3 – y3) = (x – y) (x2 + y2 + xy) (viii) (x + y + z)2 = x2 + y2 + z2 + 2(xy + yz + zx) © 2014 SSCPORTAL .IN Join Online Coaching Click Here

Numerical Aptitude http://sscportal.in Basic Algebra (ix) (x3 + y3 + z3 – 3xyz) = (x + y + z) (x2 + y2 + z2 – xy – yz – zx) (x) If x + y + z = 0, then x3 + y3 + z3 = 3xyz Also, (i) (xn – an ) is divisible by (x – a) for all values of n. (ii) (xn + an ) is divisible by (x + a) only when n is odd. (iii) (xn– an ) is divisible by (x + a) only for even values of n. (iv) (xn + an) is never divisible by (x – a). © 2014 SSCPORTAL .IN Join Online Coaching Click Here

Numerical Aptitude http://sscportal.in Basic Algebra Linear Equations Equations Linear equations in one variable Linear Equations in two variables Consistency of a System of Linear Equations © 2014 SSCPORTAL .IN Join Online Coaching Click Here

Numerical Aptitude http://sscportal.in Basic Algebra Theory of Equation Quadratic Equation To Find the Roots of Quadratic Equation Method 1: By Factorisation Method 2 : Using Formula Sum and Product of Roots of a Quadratic Equation Constructing a Quadratic Equation © 2014 SSCPORTAL .IN Join Online Coaching Click Here

UPSCPORTAL other online Courses Online Course For Civil Services Preliminary Examination सामान्य अध्ययन पेपर-1 ऑनऱाइन कोच ग िं Online Coaching For CSAT Paper -1 (GS) 2014 Online Coaching For CSAT Paper -2 (CSAT) 2014 Online Course For Civil Services Mains Examination General Studies Mains (New Pattern Paper 2,3,4,5) Contemporary Issues for Civil Services Main Examination Public Administration For Mains More IAS Online Coaching Courses http://www.upscportal.com/civilservices/courses www.upscportal.com

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