Information about SDEE: Lecture 6

Published on February 18, 2014

Author: apalmeri

Source: slideshare.net

State-Space Formulation Structural Dynamics & Earthquake Engineering The equation of motion for a SDoF oscillator reads: 2 ¨ ˙ u (t) + 2 ζ0 ω0 u(t) + ω0 u(t) = Dr Alessandro Palmeri 1 f (t) m (1) and can be posed in the alternative matrix form: ˙ y(t) = A · y(t) + b f (t) (2) where y(t) is the array of the state variables (displacement and velocity) for the oscillator: y(t) = u(t) ˙ u(t) (3) while: A= 0 1 2 −2 ζ ω −ω0 0 0 , b= 0 1/m (4)

Duhamel’s Solution Structural Dynamics & Earthquake Engineering Dr Alessandro Palmeri Let us consider a scalar ﬁrst-order inhomogeneous ODE: ˙ y (t) = A y(t) + b f (t) (5) The integral solution of Eq. (5) can be formally written as: t Θ(t − τ ) b f (τ ) dτ y(t) = Θ(t) y(0) + (6) 0 where y(0) is the initial condition at time t = 0, while the transition function Θ(t) is so deﬁned: Θ(t) = eA t (7)

Duhamel’s Solution Structural Dynamics & Earthquake Engineering Dr Alessandro Palmeri This integral solution can be extended to systems with many state variables as: t y(t) = Θ(t) · y(0) + Θ(t − τ ) · b f (τ ) dτ (8) 0 where the array y0 = y(0) collects the initial conditions at time t = 0, and the transition matrix Θ(t) is evaluated as the exponential matrix of [A t]: Θ(t) = eA t (9)

Step-by-Step Numerical Solution Structural Dynamics & Earthquake Engineering Dr Alessandro Palmeri For t = ∆t, and assuming a linear variation of the forcing term f (t) in the time interval [0, ∆t]: f (t) = f0 + f1 − f0 t ∆t (10) one can mathematically prove that the Duhamel’s integral gives: y1 = Θ(∆t) · y0 + Γ0 (∆t) · {b f0 } + Γ1 (∆t) · {b f1 } (11) where y1 = y(∆t) collects the state variables at t = ∆t, while the integration matrices Γ0 (∆t) and Γ1 (∆t) can be computed from the transition matrix Θ(∆t) and the matrix of coefﬁcients A.

Step-by-Step Numerical Solution Structural Dynamics & Earthquake Engineering Dr Alessandro Palmeri That is: Γ0 (∆t) = [Θ(∆t) − L(∆t)] · A−1 (12) Γ1 (∆t) = [L(∆t) − I2 ] · A−1 (13) in which I2 is the 2-dimensional identity matrix, while the loading matrix L(∆t) is given by: L(∆t) = 1 [Θ(∆t) − I2 ] · A−1 ∆t (14)

Step-by-Step Numerical Solution Structural Dynamics & Earthquake Engineering Moreover: Dr Alessandro Palmeri Θ(∆t) = e−ζ0 ω0 ∆t ζ0 ω0 ω0 2 ω0 − ω0 S C+ S C 1 ω0 S 0 − ζωω0 0 S (15) in which C = cos(ω 0 ∆t), S = sin(ω 0 ∆t) and ω0 = 2 1 − ζ0 ω0 , while: A−1 = − 2 ζ00 ω 1 − ω2 1 0 0 (16)

Step-by-Step Numerical Solution Structural Dynamics & Earthquake Engineering Dr Alessandro Palmeri The incremental solution offered by Eq. (11) for the time interval [0, ∆t] can be extended to a generic time instant tn = n ∆t as: yn+1 = y(tn+1 ) =Θ(∆t) · yn + Γ0 (∆t) · {b f (tn )} + Γ1 (∆t) · {b f (tn+1) } for n = 1, 2, 3, · · · (17)

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