Energy 4

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Information about Energy 4

Published on March 11, 2008

Author: zglazenburg

Source: slideshare.net

ENERGY The Potential and Kinetic Chronicles (The Law of Conservation of Mechanical Energy)

The Potential and Kinetic Chronicles

(The Law of Conservation of Mechanical Energy)

What is Energy? Energy is the ability to do work Potential Energy (PE), and Kinetic Energy (KE). Energy is measured in Joules

Energy is the ability to do work

Potential Energy (PE), and Kinetic Energy (KE).

Energy is measured in Joules

Energy cannot be created or destroyed, but can only be converted into different types of energy Law of Conservation of Energy Wind turbines transfer energy from the wind and convert it into electricity we can use.

Energy cannot be created or destroyed, but can only be converted into different types of energy

Potential Energy Is energy that is stored Chemical energy Nuclear energy Mechanical PE Gravitational PE (GPE)

Is energy that is stored

Chemical energy

Nuclear energy

Mechanical PE

Gravitational PE (GPE)

Example of a GPE Problem Gravitation PE problems have to do with an object and its position relative to the earths surface PE = mgh = (mass)(gravity)(height)

Gravitation PE problems have to do with an object and its position relative to the earths surface

PE = mgh = (mass)(gravity)(height)

Example of a GPE Problem h=60m, g=9.81m/s 2 , m=2,000kg PE= (60m)(9.81m/s 2 )(2,000kg)= 1,177,200 Joules A roller coaster of 2 metric tons is sitting at the top of the track at a height of 60 meters. What is its PE? use the PE=mgh formula

h=60m, g=9.81m/s 2 , m=2,000kg

PE= (60m)(9.81m/s 2 )(2,000kg)= 1,177,200 Joules

A roller coaster of 2 metric tons is sitting at the top of the track at a height of 60 meters. What is its PE?

use the PE=mgh formula

Mechanical PE Problems have to do with stored energy within a spring PE= 1/2kx 2 = 1/2(spring constant)( in spring length from equilibrium)

have to do with stored energy within a spring

PE= 1/2kx 2 = 1/2(spring constant)( in spring length from equilibrium)

Example of a MPE Problem A 4 gram rubber band with the spring constant of 4.3 F s /m is stretched a distance of 30 centimeters. What is the PE of the rubber band?

A 4 gram rubber band with the spring constant of 4.3 F s /m is stretched a distance of 30 centimeters. What is the PE of the rubber band?

Example of a MPE Problem Plug your information in the equation 1/2kx 2 formula k= 4.3F s /m, x=30cm=.3m PE s = .5(4.3 F s /m)(.3m)=.645 Joules PE s =.645 Joules

Plug your information in the equation 1/2kx 2 formula

k= 4.3F s /m, x=30cm=.3m

PE s = .5(4.3 F s /m)(.3m)=.645 Joules

PE s =.645 Joules

Kinetic Energy is energy of motion Mechanical KE (MKE) Radiant energy Thermal energy Electrical energy Kinetic Energy

is energy of motion

Mechanical KE (MKE)

Radiant energy

Thermal energy

Electrical energy

Example of a MKE Problem Mechanical KE problems involve objects that are in motion. PE=KE or mgh=1/2mv 2 = 1/2(mass)(velocity 2 ) If one knows the PE within a certain system, then one can find the variables such as v (velocity)

Mechanical KE problems involve objects that are in motion.

PE=KE or mgh=1/2mv 2 = 1/2(mass)(velocity 2 )

If one knows the PE within a certain system, then one can find the variables such as v (velocity)

Example of a MKE problem A roller coaster of 2 metric tons is sitting at the top of the track at a height of 60 meters has a PE of 1,177,200 . What is the velocity when it reaches the ground? PE=KE, 1,177,200=1/2(2,000)(v 2 ) sqrt(1,177,200/1,000)=sqrt(v 2 ) v=34.3m/s

A roller coaster of 2 metric tons is sitting at the top of the track at a height of 60 meters has a PE of 1,177,200 . What is the velocity when it reaches the ground?

PE=KE, 1,177,200=1/2(2,000)(v 2 )

sqrt(1,177,200/1,000)=sqrt(v 2 )

v=34.3m/s

PE of a spring problem A 4 gram rubber band with the spring constant of 4.3 N/m is fired after being stretched a distance of 30 centimeters it has a PE is .645 Joules. What is the velocity when it is fired? PE s =KE, .645=.5(.004kg)(v 2 ) sqrt(.645/.002)=sqrt(v 2 ) v=18

A 4 gram rubber band with the spring constant of 4.3 N/m is fired after being stretched a distance of 30 centimeters it has a PE is .645 Joules. What is the velocity when it is fired?

PE s =KE, .645=.5(.004kg)(v 2 )

sqrt(.645/.002)=sqrt(v 2 )

v=18

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