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Information about Dividing Polynomials Slide Share

Published on December 5, 2007

Author: krillion

Source: slideshare.net

I have added to the original presentation in response to one of the comments.... the result of 'x' is correct on slide 7, take a look at the new version of this ppt to clear up any confusion about why...

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Algebraic long division Divide 2 x ³ + 3 x ² - x + 1 by x + 2 x + 2 is the divisor The quotient will be here. 2x³ + 3x² - x + 1 is the dividend

Algebraic long division First divide the first term of the dividend, 2 x ³, by x (the first term of the divisor). This gives 2x². This will be the first term of the quotient.

Algebraic long division Now multiply 2x² by x + 2 and subtract

Algebraic long division Bring down the next term, - x .

Algebraic long division Now divide – x ², the first term of – x ² - x , by x , the first term of the divisor which gives – x .

Algebraic long division Multiply –x by x + 2 To get a result of:

Algebraic long division Now subtract ** remember, you must subtract both the –x 2 term and the -2x term

Algebraic long division Now combine like terms (since we subtracted two negative terms they both turned into positive terms) {

Algebraic long division Bring down the next term, 1

Algebraic long division Divide x , the first term of x + 1, by x , the first term of the divisor which gives 1

Algebraic long division Multiply x + 2 by 1 and subtract

Algebraic long division The remainder is –1. The quotient is 2x² - x + 1

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