Algebra II

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Information about Algebra II
Education

Published on June 15, 2007

Author: Woodwork

Source: authorstream.com

Algebra II:  Algebra II By Monica Yuskaitis Definitions:  Definitions Equation – A mathematical sentence stating that 2 expressions are equal. 12 – 3 = 9 8 + 4 = 12 Definitions:  Definitions Equation – A mathematical sentence with an equals sign. 16 – 5 = 11 14 + 3 = 17 Definitions:  Definitions Equals Sign (=) Means that the amount is the same on both sides. 4 + 2 = 6 5 – 2 = 3 An Equation is like a balance scale. Everything must be equal on both sides.:  An Equation is like a balance scale. Everything must be equal on both sides. 10 5 + 5 = When the amounts are equal on both sides it is a true equation.:  When the amounts are equal on both sides it is a true equation. 12 6 + 6 = When the amounts are unequal on both sides it is a false equation.:  When the amounts are unequal on both sides it is a false equation. 8 2 + 2 = When an amount is unknown on one side of the equation it is an open equation.:  When an amount is unknown on one side of the equation it is an open equation. 7 n + 2 = When you find a number for n you change the open equation to a true equation. You solve the equation.:  When you find a number for n you change the open equation to a true equation. You solve the equation. 7 n + 2 = 5 Are these equations true, false or open?:  Are these equations true, false or open? 11 - 3 = 5 13 + 4 = 17 N + 4 = 7 12 – 3 = 8 3 + v = 13 15 – 6 = 9 false true open false open true Definitions:  Definitions Inverse operation – the opposite operation used to undo the first. 4 + 3 = 7 7 – 4 = 3 6 x 6 = 36 36 / 6 = 6 How to solve an addition equation:  How to solve an addition equation Use the inverse operation for addition which is subtraction m + 8 = 12 12 - 8 = 4 m = 4 4 + 8 = 12 How to solve a subtraction equation:  How to solve a subtraction equation Use the inverse operation for subtraction which is addition m - 3 = 5 5 + 3 = 8 m = 8 8 - 3 = 5 Solve these equations using the inverse operations:  Solve these equations using the inverse operations n + 4 = 7 n – 5 = 4 n + 4 = 17 n – 6 = 13 n + 7 = 15 n – 8 = 17 3 9 13 19 8 9 Commutative Property:  Commutative Property 5 + 4 = 9 4 + 5 = 9 a + b = c b + a = c 6 + 3 = 9 3 + 6 = 9 x+ y = z y + x = z 3 + 4 + 1 = 8 1 + 3 + 4 = 8 Solve these equations using the commutative property:  Solve these equations using the commutative property n + 7 = 7 + 4 m + 2 = 2 + 5 z + 3 = 3 + 9 g + 6 = 6 + 11 s + 4 = 4 + 20 c + 8 = 8 + 32 n = 4 m = 5 z = 9 g = 11 s = 20 c = 32 The Identity Property of Addition:  The Identity Property of Addition 7 + 0 = 7 a + 0 = a 8 + 0 = 8 c + 0 = c 2 + 0 = 2 Use the Identity Property of addition to solve these problems:  Use the Identity Property of addition to solve these problems n + 0 = 8 b + 0 = 7 m + 0 = 3 v + 0 = 5 w + 0 = 4 r + 0 = 2 n = 8 b = 7 m = 3 v = 5 w = 4 r = 2 Subtraction Rules of zero:  Subtraction Rules of zero 7 – 7 = 0 n – n = 0 4 – 0 = 4 n – 0 = n Find the value of n using the rules of subtraction:  Find the value of n using the rules of subtraction n - 8 = 0 n – 9 = 0 n – 0 = 7 n – 0 = 9 n – 7 = 0 n – 0 = 5 n = 8 n = 9 n = 7 n = 9 n = 7 n = 5 Write an equation for these problems using a variable:  Write an equation for these problems using a variable Timothy got 72 right on his timed test in July. He got 99 right on this same test in November. Jasmin runs 15 minutes before school and 30 minutes after school. One zinger costs 25 cents. Issak bought 4. 72 + n = 99 or 99 – 72 = n 15 + 30 = n 4 x 25 = n

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