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Information about 8004 side splitter 2014

Published on March 11, 2014

Author: jbianco9910

Source: slideshare.net

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Given Prove RSPQ// QT SQ PT RP R P T Q S

Objective •Students will prove and apply the side- splitter theorem and other similarity properties.

Side-splitter Theorem •A line parallel to one side of a triangle divides the other two sides proportionally

Use the side-splitter to solve for x and y: 6 18 x 6 y

Check It Out! Example 1 Find PN. Substitute in the given values. Cross Products Prop.2PN = 15 PN = 7.5 Divide both sides by 2. Use the Triangle Proportionality Theorem.

Example 2: Verifying Segments are Parallel Verify that . Since , by the Converse of the Triangle Proportionality Theorem.

Check It Out! Example 2 AC = 36 cm, and BC = 27 cm. Verify that . Since , by the Converse of the Triangle Proportionality Theorem.

Two Transversal Proportionality Corollary •Two or more parallel lines divide two transversals proportionally c d a b a b = c d

So, you might want to ask yourself:• Can I find x? • NO YOU MUST KNOW LINES ARE // x 3 5 9

Solve for x 5x 15 3x 4x

Triangle Angle-Bisector Theorem • If a ray bisects an angle of a triangle then it divides the opposite side into segments proportional to the other two sides

The previous theorems and corollary lead to the following conclusion.

Example 4: Using the Triangle Angle Bisector Theorem Find PS and SR. by the ∆ Bisector Theorem. x = 30 PS = x – 2 SR = x + 5 = 30 – 2 = 28 = 30 + 5 = 35

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