# 14.5.8 Example 1 Part 5

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Information about 14.5.8 Example 1 Part 5

Published on July 15, 2009

Author: taliacarbis

Source: slideshare.net

17 VAR

S= √(Q2 + P2) S = √ (17² + 1500²) S = 1500.09 S =1.5 kW

true power Power factor (pf) = apparent power 1.5kW = 1.5009 kVA or 0.99994

1.50009 kVA Total current = 240 Volts or 6.25 amps

Refer to Electrical Trade Principles p. 234 - 240 by Hampson & Hanssen

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